Let Sn=(2n)2−(2n−1)2+(2n−2)2−(2n−3)2+⋯+22−12S_n = (2n)^2 - (2n-1)^2 + (2n-2)^2 - (2n-3)^2 + \dots + 2^2 - 1^2Sn=(2n)2−(2n−1)2+(2n−2)2−(2n−3)2+⋯+22−12. Report the value of S50S_{50}S50.
